iod ([info]iod) wrote,
@ 2006-08-05 16:49:00
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Entry tags:academic dishonesty, thesis

I've been reading up for my thesis, on voting behavior. Anyway, I'm currently reading an article that deals with the concept of party identification. It brings data from two panel surveys in Germany and Britain, that deals with which parties respondents identify with over time.

At one point, they discuss people who named only one of the large parties, and did so at least once during the survey years (9 in the UK, 14 in Germany). They say that there are two types of people - those who vote for that party always (or almost always), and those that vote so "haphazardly", or at random. In their own words: "Of those who do not always choose their party, the mean rate of selection is four in eight years, indicating a pattern that resembles a coin toss between “yes” and “no” for each year." Seems reasonable. Only that merely stating the mean number of times they chose that party doesn't really indicate anything of the sort. It could, but it doesn't have to. It doesn't take a mathematical genius to know that there would have to be a "normal" curve if that was indeed the case - if people chose the party at random, most people would chose it 4 times, and the least would choose it 1 or 7 times.

Let's look at the graph, shall we?


graph


Hrm, the results are exactly opposite to what we would be looking for! Not only is there no peak at 4, there is, in fact, a low-point just there. If anything, this data shows that people don't choose "haphazardly", and only a few are so unstable as to be as likely to choose the party as not.

This sort of stupid academic dishonesty really annoys me. I mean, the graph is right there in front of me - I'm not stupid. You're only going to fool the poor saps who don't know shit about statistics. That hardly seems fair or smart. It's abuse. It also, as it so happens, topples their basic hypothesis in this article (from the abstract: "Most take a definitively
negative stance towards one of the parties and a positive stance towards the other major party. Of these, about half display behavior that reflects a psychological commitment and about half are as likely as not to pick that party when asked").

Fa.




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(Anonymous)
2006-08-06 04:32 am UTC (link)
Is it possible that the author of the article confused uniform distribution with "as likely as not to pick that party when asked"?
Because once you chop off those who voted for the party 8-9 times, you very nearly have uniform distribution. Perhaps this is the source of the error.

(Reply to this)

Academic amateurism
(Anonymous)
2006-08-08 08:21 am UTC (link)
Calling this analysis dishonest seems to me like it's giving woever wrote it too much credit. Not only is the analysis ridiculous, the graph itself probably is a totally meaningless collection of data. Here's a nother possible explanantion of the same data: NONE of the voters ever switch parties, so that about 40% of the participants who are at the appropriate ages voted 9 times for the same party, some people even though of the same age group missed a single election for some reason and therefore voted 8 times for the same party, younger people participated in a lower number of elections and therefore voted less times for the same party (but never for another party), since the population of Britain does not grow that fast the number of voters added per election is rather constant.

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Re: Academic amateurism
[info]iod
2006-08-08 08:27 am UTC (link)
No, it's not that bad. This survey didn't have anything to do with elections - it's a panel survey which asks respondents every year which party they support the most. The data they used only included those who answered the survey each of the nine years - all of which were at least 18 years old during the first wave.

(Reply to this) (Parent)(Thread)

Re: Academic amateurism
(Anonymous)
2006-08-08 12:17 pm UTC (link)
In that case how comes the number of people who named Conservatives once is not even close to the number of people who named Labour 8 times?

(Reply to this) (Parent)(Thread)

Re: Academic amateurism
[info]iod
2006-08-08 12:24 pm UTC (link)
what do the two numbers have to do with each other? This table depicts the number of times that *people who voted for one of the parties at least once and never for the other*, voted for that party. Hint: there are other options (e.g., none at all, "third" parties).

(Reply to this) (Parent)


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